What is the general solution for sin(((t^2))/2)=-1 ?

The general solution for sin(((t^2))/2)=-1 is t=sqrt(3pi+4pin),t=-sqrt(3pi+4pin)

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sin(((t^2))/2)=-1

sin (\frac{( t ^{2} )}{2}) = - 1

t = 3 π + 4 πn, t = - 3 π + 4 πn

Solution steps

sin (\frac{( t ^{2} )}{2}) = - 1

General solutions for

sin (\frac{t ^{2}}{2}) = - 1

\frac{t ^{2}}{2} = \frac{3 π}{2} + 2 πn

Solve

\frac{t ^{2}}{2} = \frac{3 π}{2} + 2 πn : t = 3 π + 4 πn, t = - 3 π + 4 πn

t = 3 π + 4 πn, t = - 3 π + 4 πn

9 sin^{2} (x) tan (x) = 4 tan (x)

cos^{2} (x) - 3 cos (x) = 0

- 2 cos (θ) = 0

2 cos^{2} (x) + 15 sin (x) = 9

cot (θ) = 1.413

What is the general solution for sin(((t^2))/2)=-1 ?
The general solution for sin(((t^2))/2)=-1 is t=sqrt(3pi+4pin),t=-sqrt(3pi+4pin)