What is the general solution for solvefor x,2y=sin(2x) ?

The general solution for solvefor x,2y=sin(2x) is x=(arcsin(2y))/2+pin,x= pi/2+(arcsin(-2y))/2+pin

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solvefor x,2y=sin(2x)

solve for

x, 2 y = sin (2 x)

x = \frac{arcsin ( 2 y )}{2} + πn, x = \frac{π}{2} + \frac{arcsin ( - 2 y )}{2} + πn

Solution steps

2 y = sin (2 x)

Switch sides

sin (2 x) = 2 y

Apply trig inverse properties

2 x = arcsin (2 y) + 2 πn, 2 x = π + arcsin (- 2 y) + 2 πn

Solve

2 x = arcsin (2 y) + 2 πn : x = \frac{arcsin ( 2 y )}{2} + πn

Solve

2 x = π + arcsin (- 2 y) + 2 πn : x = \frac{π}{2} + \frac{arcsin ( - 2 y )}{2} + πn

x = \frac{arcsin ( 2 y )}{2} + πn, x = \frac{π}{2} + \frac{arcsin ( - 2 y )}{2} + πn

- csc (θ) + 5 = cot (θ) + 6

sin (θ) - 0.2 \cdot cos (θ) = 0.11836

2 sin^{2} (x) - 3 = cos (x) - 2

cos (\frac{x}{2}) = 1 - cos (\frac{x}{2})

3 = 4 - 2 sin (θ)

What is the general solution for solvefor x,2y=sin(2x) ?
The general solution for solvefor x,2y=sin(2x) is x=(arcsin(2y))/2+pin,x= pi/2+(arcsin(-2y))/2+pin