What is the general solution for -cos(20.02t)=sin(20t) ?

The general solution for -cos(20.02t)=sin(20t) is t=25pi(4n+1),t=-(6.28318…n+pi/2)/(40.02)

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-cos(20.02t)=sin(20t)

- cos (20.02 t) = sin (20 t)

t = 25 π (4 n + 1), t = - \frac{6.28318 \dots n + \frac{π}{2}}{40.02}

Solution steps

- cos (20.02 t) = sin (20 t)

Multiply by

- 1

cos (20.02 t) = - sin (20 t)

Rewrite using trig identities

sin (\frac{π}{2} - 20.02 t) = sin (- (20 t))

Apply trig inverse properties

- (20 t) = \frac{π}{2} - 20.02 t + 2 πn, - (20 t) = π - (\frac{π}{2} - 20.02 t) + 2 πn

- (20 t) = \frac{π}{2} - 20.02 t + 2 πn : t = 25 π (4 n + 1)

- (20 t) = π - (\frac{π}{2} - 20.02 t) + 2 πn : t = - \frac{6.28318 \dots n + \frac{π}{2}}{40.02}

t = 25 π (4 n + 1), t = - \frac{6.28318 \dots n + \frac{π}{2}}{40.02}

sin^{3} (x) + 3 sin^{2} (x) + 2 sin (x) = 0, 0 \leq x < 2 π

sin (2 x - \frac{π}{6}) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

\frac{cos ( x )}{2} = \frac{- 3}{2}

b, a = arccos (\frac{a ^{2} - b ^{2} - c ^{2}}{- 2 b c})

4 cos (θ) - 1 = 0

What is the general solution for -cos(20.02t)=sin(20t) ?
The general solution for -cos(20.02t)=sin(20t) is t=25pi(4n+1),t=-(6.28318…n+pi/2)/(40.02)