What is the general solution for sin(2x-pi/6)=0,0<= x<= 360 ?

The general solution for sin(2x-pi/6)=0,0<= x<= 360 is x=15,x=105,x=195,x=285

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sin(2x-pi/6)=0,0<= x<= 360

sin (2 x - \frac{π}{6}) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

x = 1 5^{\circ}, x = 10 5^{\circ}, x = 19 5^{\circ}, x = 28 5^{\circ}

Solution steps

sin (2 x - \frac{π}{6}) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

General solutions for

sin (2 x - 3 0^{\circ}) = 0

2 x - 3 0^{\circ} = 0 + 36 0^{\circ} n, 2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n

Solve

2 x - 3 0^{\circ} = 0 + 36 0^{\circ} n : x = 18 0^{\circ} n + 1 5^{\circ}

Solve

2 x - 3 0^{\circ} = 18 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

x = 18 0^{\circ} n + 1 5^{\circ}, x = 18 0^{\circ} n + 9 0^{\circ} + 1 5^{\circ}

Solutions for the range

0 \leq x \leq 36 0^{\circ}

x = 1 5^{\circ}, x = 10 5^{\circ}, x = 19 5^{\circ}, x = 28 5^{\circ}

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What is the general solution for sin(2x-pi/6)=0,0<= x<= 360 ?
The general solution for sin(2x-pi/6)=0,0<= x<= 360 is x=15,x=105,x=195,x=285