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Popular Trigonometry >

sin(θ)-0.2cos(θ)=0.6377

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Solution

sin(θ)−0.2cos(θ)=0.6377

Solution

θ=2.66345…+2πn,θ=0.87293…+2πn
+1
Degrees
θ=152.60452…∘+360∘n,θ=50.01533…∘+360∘n
Solution steps
sin(θ)−0.2cos(θ)=0.6377
Add 0.2cos(θ) to both sidessin(θ)=0.6377+0.2cos(θ)
Square both sidessin2(θ)=(0.6377+0.2cos(θ))2
Subtract (0.6377+0.2cos(θ))2 from both sidessin2(θ)−0.40666129−0.25508cos(θ)−0.04cos2(θ)=0
Rewrite using trig identities
−0.40666129+sin2(θ)−0.04cos2(θ)−0.25508cos(θ)
Use the Pythagorean identity: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−0.40666129+1−cos2(θ)−0.04cos2(θ)−0.25508cos(θ)
Simplify −0.40666129+1−cos2(θ)−0.04cos2(θ)−0.25508cos(θ):−1.04cos2(θ)−0.25508cos(θ)+0.59333871
−0.40666129+1−cos2(θ)−0.04cos2(θ)−0.25508cos(θ)
Add similar elements: −cos2(θ)−0.04cos2(θ)=−1.04cos2(θ)=−0.40666129+1−1.04cos2(θ)−0.25508cos(θ)
Add/Subtract the numbers: −0.40666129+1=0.59333871=−1.04cos2(θ)−0.25508cos(θ)+0.59333871
=−1.04cos2(θ)−0.25508cos(θ)+0.59333871
0.59333871−0.25508cos(θ)−1.04cos2(θ)=0
Solve by substitution
0.59333871−0.25508cos(θ)−1.04cos2(θ)=0
Let: cos(θ)=u0.59333871−0.25508u−1.04u2=0
0.59333871−0.25508u−1.04u2=0:u=−2.080.25508+2.53335484​​,u=2.082.53335484​−0.25508​
0.59333871−0.25508u−1.04u2=0
Write in the standard form ax2+bx+c=0−1.04u2−0.25508u+0.59333871=0
Solve with the quadratic formula
−1.04u2−0.25508u+0.59333871=0
Quadratic Equation Formula:
For a=−1.04,b=−0.25508,c=0.59333871u1,2​=2(−1.04)−(−0.25508)±(−0.25508)2−4(−1.04)⋅0.59333871​​
u1,2​=2(−1.04)−(−0.25508)±(−0.25508)2−4(−1.04)⋅0.59333871​​
(−0.25508)2−4(−1.04)⋅0.59333871​=2.53335484​
(−0.25508)2−4(−1.04)⋅0.59333871​
Apply rule −(−a)=a=(−0.25508)2+4⋅1.04⋅0.59333871​
Apply exponent rule: (−a)n=an,if n is even(−0.25508)2=0.255082=0.255082+4⋅0.59333871⋅1.04​
Multiply the numbers: 4⋅1.04⋅0.59333871=2.46828…=0.255082+2.46828…​
0.255082=0.0650658064=0.0650658064+2.46828…​
Add the numbers: 0.0650658064+2.46828…=2.53335484=2.53335484​
u1,2​=2(−1.04)−(−0.25508)±2.53335484​​
Separate the solutionsu1​=2(−1.04)−(−0.25508)+2.53335484​​,u2​=2(−1.04)−(−0.25508)−2.53335484​​
u=2(−1.04)−(−0.25508)+2.53335484​​:−2.080.25508+2.53335484​​
2(−1.04)−(−0.25508)+2.53335484​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅1.040.25508+2.53335484​​
Multiply the numbers: 2⋅1.04=2.08=−2.080.25508+2.53335484​​
Apply the fraction rule: −ba​=−ba​=−2.080.25508+2.53335484​​
u=2(−1.04)−(−0.25508)−2.53335484​​:2.082.53335484​−0.25508​
2(−1.04)−(−0.25508)−2.53335484​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅1.040.25508−2.53335484​​
Multiply the numbers: 2⋅1.04=2.08=−2.080.25508−2.53335484​​
Apply the fraction rule: −b−a​=ba​0.25508−2.53335484​=−(2.53335484​−0.25508)=2.082.53335484​−0.25508​
The solutions to the quadratic equation are:u=−2.080.25508+2.53335484​​,u=2.082.53335484​−0.25508​
Substitute back u=cos(θ)cos(θ)=−2.080.25508+2.53335484​​,cos(θ)=2.082.53335484​−0.25508​
cos(θ)=−2.080.25508+2.53335484​​,cos(θ)=2.082.53335484​−0.25508​
cos(θ)=−2.080.25508+2.53335484​​:θ=arccos(−2.080.25508+2.53335484​​)+2πn,θ=−arccos(−2.080.25508+2.53335484​​)+2πn
cos(θ)=−2.080.25508+2.53335484​​
Apply trig inverse properties
cos(θ)=−2.080.25508+2.53335484​​
General solutions for cos(θ)=−2.080.25508+2.53335484​​cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnθ=arccos(−2.080.25508+2.53335484​​)+2πn,θ=−arccos(−2.080.25508+2.53335484​​)+2πn
θ=arccos(−2.080.25508+2.53335484​​)+2πn,θ=−arccos(−2.080.25508+2.53335484​​)+2πn
cos(θ)=2.082.53335484​−0.25508​:θ=arccos(2.082.53335484​−0.25508​)+2πn,θ=2π−arccos(2.082.53335484​−0.25508​)+2πn
cos(θ)=2.082.53335484​−0.25508​
Apply trig inverse properties
cos(θ)=2.082.53335484​−0.25508​
General solutions for cos(θ)=2.082.53335484​−0.25508​cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnθ=arccos(2.082.53335484​−0.25508​)+2πn,θ=2π−arccos(2.082.53335484​−0.25508​)+2πn
θ=arccos(2.082.53335484​−0.25508​)+2πn,θ=2π−arccos(2.082.53335484​−0.25508​)+2πn
Combine all the solutionsθ=arccos(−2.080.25508+2.53335484​​)+2πn,θ=−arccos(−2.080.25508+2.53335484​​)+2πn,θ=arccos(2.082.53335484​−0.25508​)+2πn,θ=2π−arccos(2.082.53335484​−0.25508​)+2πn
Verify solutions by plugging them into the original equation
Check the solutions by plugging them into sin(θ)−0.2cos(θ)=0.6377
Remove the ones that don't agree with the equation.
Check the solution arccos(−2.080.25508+2.53335484​​)+2πn:True
arccos(−2.080.25508+2.53335484​​)+2πn
Plug in n=1arccos(−2.080.25508+2.53335484​​)+2π1
For sin(θ)−0.2cos(θ)=0.6377plug inθ=arccos(−2.080.25508+2.53335484​​)+2π1sin(arccos(−2.080.25508+2.53335484​​)+2π1)−0.2cos(arccos(−2.080.25508+2.53335484​​)+2π1)=0.6377
Refine0.6377=0.6377
⇒True
Check the solution −arccos(−2.080.25508+2.53335484​​)+2πn:False
−arccos(−2.080.25508+2.53335484​​)+2πn
Plug in n=1−arccos(−2.080.25508+2.53335484​​)+2π1
For sin(θ)−0.2cos(θ)=0.6377plug inθ=−arccos(−2.080.25508+2.53335484​​)+2π1sin(−arccos(−2.080.25508+2.53335484​​)+2π1)−0.2cos(−arccos(−2.080.25508+2.53335484​​)+2π1)=0.6377
Refine−0.28255…=0.6377
⇒False
Check the solution arccos(2.082.53335484​−0.25508​)+2πn:True
arccos(2.082.53335484​−0.25508​)+2πn
Plug in n=1arccos(2.082.53335484​−0.25508​)+2π1
For sin(θ)−0.2cos(θ)=0.6377plug inθ=arccos(2.082.53335484​−0.25508​)+2π1sin(arccos(2.082.53335484​−0.25508​)+2π1)−0.2cos(arccos(2.082.53335484​−0.25508​)+2π1)=0.6377
Refine0.6377=0.6377
⇒True
Check the solution 2π−arccos(2.082.53335484​−0.25508​)+2πn:False
2π−arccos(2.082.53335484​−0.25508​)+2πn
Plug in n=12π−arccos(2.082.53335484​−0.25508​)+2π1
For sin(θ)−0.2cos(θ)=0.6377plug inθ=2π−arccos(2.082.53335484​−0.25508​)+2π1sin(2π−arccos(2.082.53335484​−0.25508​)+2π1)−0.2cos(2π−arccos(2.082.53335484​−0.25508​)+2π1)=0.6377
Refine−0.89473…=0.6377
⇒False
θ=arccos(−2.080.25508+2.53335484​​)+2πn,θ=arccos(2.082.53335484​−0.25508​)+2πn
Show solutions in decimal formθ=2.66345…+2πn,θ=0.87293…+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for sin(θ)-0.2cos(θ)=0.6377 ?

    The general solution for sin(θ)-0.2cos(θ)=0.6377 is θ=2.66345…+2pin,θ=0.87293…+2pin
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