What is the general solution for (tan(x)-1)(2cos(x)+1)=0 ?

The general solution for (tan(x)-1)(2cos(x)+1)=0 is x= pi/4+pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin

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(tan(x)-1)(2cos(x)+1)=0

(tan (x) - 1) (2 cos (x) + 1) = 0

x = \frac{π}{4} + πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

(tan (x) - 1) (2 cos (x) + 1) = 0

Solving each part separately

tan (x) - 1 = 0 or 2 cos (x) + 1 = 0

tan (x) - 1 = 0 : x = \frac{π}{4} + πn

2 cos (x) + 1 = 0 : x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

cot (θ) = - 3, sin (θ) < 0

tan (x) sin (x) + cos (x) = 1

6 sin (t) = 0

(500 \cdot 9.8 \cdot l (1 - cos (θ))) = 0.018

sec (x) = \frac{sin ( x )}{cos ( x )}

What is the general solution for (tan(x)-1)(2cos(x)+1)=0 ?
The general solution for (tan(x)-1)(2cos(x)+1)=0 is x= pi/4+pin,x=(2pi)/3+2pin,x=(4pi)/3+2pin