What is the general solution for sin^2(x)=cos(x)-cos^2(x) ?

The general solution for sin^2(x)=cos(x)-cos^2(x) is x=2pin

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sin^2(x)=cos(x)-cos^2(x)

sin^{2} (x) = cos (x) - cos^{2} (x)

x = 2 πn

Solution steps

sin^{2} (x) = cos (x) - cos^{2} (x)

Subtract

cos (x) - cos^{2} (x)

from both sides

sin^{2} (x) - cos (x) + cos^{2} (x) = 0

Rewrite using trig identities

- cos (x) + 1 = 0

Move

1

to the right side

- cos (x) = - 1

Divide both sides by

- 1

cos (x) = 1

General solutions for

cos (x) = 1

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn

x, arcsin (x + y) = 0

1 + cos (π x) = sin (π x)

sin (x - 1 5^{\circ}) = cos (2 0^{\circ} + x)

15 sin^{2} (x) - 17 sin (x) + 4 = 0

cos (x) = \frac{451.1}{497}

What is the general solution for sin^2(x)=cos(x)-cos^2(x) ?
The general solution for sin^2(x)=cos(x)-cos^2(x) is x=2pin