What is the general solution for 3sin(θ/4)-3/2 =0,0<= θ<= 2pi ?

The general solution for 3sin(θ/4)-3/2 =0,0<= θ<= 2pi is θ=(2pi)/3

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3sin(θ/4)-3/2 =0,0<= θ<= 2pi

3 sin (\frac{θ}{4}) - \frac{3}{2} = 0, 0 \leq θ \leq 2 π

θ = \frac{2 π}{3}

Solution steps

3 sin (\frac{θ}{4}) - \frac{3}{2} = 0, 0 \leq θ \leq 2 π

Move

\frac{3}{2}

to the right side

3 sin (\frac{θ}{4}) = \frac{3}{2}

Divide both sides by

3

sin (\frac{θ}{4}) = \frac{1}{2}

General solutions for

sin (\frac{θ}{4}) = \frac{1}{2}

\frac{θ}{4} = \frac{π}{6} + 2 πn, \frac{θ}{4} = \frac{5 π}{6} + 2 πn

Solve

\frac{θ}{4} = \frac{π}{6} + 2 πn : θ = \frac{2 π}{3} + 8 πn

Solve

\frac{θ}{4} = \frac{5 π}{6} + 2 πn : θ = \frac{10 π}{3} + 8 πn

θ = \frac{2 π}{3} + 8 πn, θ = \frac{10 π}{3} + 8 πn

Solutions for the range

0 \leq θ \leq 2 π

θ = \frac{2 π}{3}

\frac{1 - tan ^{2} ( A )}{2 tan ( A )} = cot (A)

cos (4 θ) = cos (2 θ), 18 0^{\circ} \leq θ \leq 36 0^{\circ}

2 sin (x) = cos (x)

8 cos (2 x) = 8 - 8 cos (2 x)

- (2) cos (10 t) = (6) sin (10 t)

What is the general solution for 3sin(θ/4)-3/2 =0,0<= θ<= 2pi ?
The general solution for 3sin(θ/4)-3/2 =0,0<= θ<= 2pi is θ=(2pi)/3