What is the general solution for 8cos(2x)=8-8cos(2x) ?

The general solution for 8cos(2x)=8-8cos(2x) is x= pi/6+pin,x=(5pi)/6+pin

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8cos(2x)=8-8cos(2x)

8 cos (2 x) = 8 - 8 cos (2 x)

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

8 cos (2 x) = 8 - 8 cos (2 x)

Solve by substitution

cos (2 x) = \frac{1}{2}

cos (2 x) = \frac{1}{2} : x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Combine all the solutions

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

- (2) cos (10 t) = (6) sin (10 t)

cot (x) = \frac{1}{4}

tan (x) = 0, 0 < x < 2 π

x, sin (x) + cos (y) = 2 y

4 sin (b) + 8 = 0

What is the general solution for 8cos(2x)=8-8cos(2x) ?
The general solution for 8cos(2x)=8-8cos(2x) is x= pi/6+pin,x=(5pi)/6+pin