What is the general solution for sin(2x)=(sqrt(3))/2 ,0<= x<= 360 ?

The general solution for sin(2x)=(sqrt(3))/2 ,0<= x<= 360 is x=30,x=60,x=210,x=240

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sin(2x)=(sqrt(3))/2 ,0<= x<= 360

sin (2 x) = \frac{3}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

x = 3 0^{\circ}, x = 6 0^{\circ}, x = 21 0^{\circ}, x = 24 0^{\circ}

Solution steps

sin (2 x) = \frac{3}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

General solutions for

sin (2 x) = \frac{3}{2}

2 x = 6 0^{\circ} + 36 0^{\circ} n, 2 x = 12 0^{\circ} + 36 0^{\circ} n

Solve

2 x = 6 0^{\circ} + 36 0^{\circ} n : x = 3 0^{\circ} + 18 0^{\circ} n

Solve

2 x = 12 0^{\circ} + 36 0^{\circ} n : x = 6 0^{\circ} + 18 0^{\circ} n

x = 3 0^{\circ} + 18 0^{\circ} n, x = 6 0^{\circ} + 18 0^{\circ} n

Solutions for the range

0 \leq x \leq 36 0^{\circ}

x = 3 0^{\circ}, x = 6 0^{\circ}, x = 21 0^{\circ}, x = 24 0^{\circ}

3 sin^{2} (x) + 8 cos^{2} (x) = 6

tan (θ) = \frac{2}{8}

4 tan^{2} (x) + 7 tan (x) - 4 = 0, cot (2 x)

tan^{3} (x) = tan^{2} (x), 0 \leq x \leq 2 π

11.75 = 5 sin (\frac{π t}{6} - \frac{7 π}{6}) + 8

What is the general solution for sin(2x)=(sqrt(3))/2 ,0<= x<= 360 ?
The general solution for sin(2x)=(sqrt(3))/2 ,0<= x<= 360 is x=30,x=60,x=210,x=240