zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

tan(A/2)=sqrt(0.62)

解答

tan (\frac{A}{2}) = 0.62

解答

A = 2 \cdot 0.66701 \dots + 2 πn

+1

度数

A = 76.43384 \dots^{\circ} + 36 0^{\circ} n

求解步骤

tan (\frac{A}{2}) = 0.62

使用反三角函数性质

tan (\frac{A}{2}) = 0.62

tan (\frac{A}{2}) = 0.62

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

\frac{A}{2} = arctan (0.62) + πn

\frac{A}{2} = arctan (0.62) + πn

解

\frac{A}{2} = arctan (0.62) + πn : A = 2 arctan (0.62) + 2 πn

\frac{A}{2} = arctan (0.62) + πn

在两边乘以

2

\frac{A}{2} = arctan (0.62) + πn

在两边乘以

2

\frac{2 A}{2} = 2 arctan (0.62) + 2 πn

化简

A = 2 arctan (0.62) + 2 πn

A = 2 arctan (0.62) + 2 πn

A = 2 arctan (0.62) + 2 πn

以小数形式表示解

A = 2 \cdot 0.66701 \dots + 2 πn

作图

流行的例子

2sin(θ)-1=0,(0,2pi)

2 sin (θ) - 1 = 0, (0, 2 π)

solvefor a,r=cos(2a)

so l v e f or a, r = cos (2 a)

cos(2t)+cos(t)=0

cos (2 t) + cos (t) = 0

tan(x)=3tan(1/2 x)

tan (x) = 3 tan (\frac{1}{2} x)

cos(t)=(-5)/(13), 1/2 pi<t<pi

cos (t) = \frac{- 5}{13}, \frac{1}{2} π < t < π