What is the general solution for 3cos(θ)-3=0 ?

The general solution for 3cos(θ)-3=0 is θ=2pin

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3cos(θ)-3=0

3 cos (θ) - 3 = 0

θ = 2 πn

Degrees

θ = 0^{\circ} + 36 0^{\circ} n

Solution steps

3 cos (θ) - 3 = 0

Move

3

to the right side

3 cos (θ) - 3 = 0

Add

3

to both sides

3 cos (θ) - 3 + 3 = 0 + 3

Simplify

3 cos (θ) = 3

3 cos (θ) = 3

Divide both sides by

3

3 cos (θ) = 3

Divide both sides by

3

\frac{3 cos ( θ )}{3} = \frac{3}{3}

Simplify

cos (θ) = 1

cos (θ) = 1

General solutions for

cos (θ) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = 0 + 2 πn

θ = 0 + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 0 + 2 πn

0 + 2 πn = 2 πn

θ = 2 πn

θ = 2 πn

(3 tan (x) - 1) (tan (x) - 3) = 0

sin (X) = \frac{2}{2}

x, 2 + sin (x) = 0

cosh (\frac{zz}{2}) = 0

t, 2 cos (t) = x

What is the general solution for 3cos(θ)-3=0 ?
The general solution for 3cos(θ)-3=0 is θ=2pin