What is the general solution for sin(X)=(sqrt(2))/2 ?

The general solution for sin(X)=(sqrt(2))/2 is X= pi/4+2pin,X=(3pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(X)=(sqrt(2))/2

sin (X) = \frac{2}{2}

X = \frac{π}{4} + 2 πn, X = \frac{3 π}{4} + 2 πn

Degrees

X = 4 5^{\circ} + 36 0^{\circ} n, X = 13 5^{\circ} + 36 0^{\circ} n

Solution steps

sin (X) = \frac{2}{2}

General solutions for

sin (X) = \frac{2}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

X = \frac{π}{4} + 2 πn, X = \frac{3 π}{4} + 2 πn

X = \frac{π}{4} + 2 πn, X = \frac{3 π}{4} + 2 πn

x, 2 + sin (x) = 0

cosh (\frac{zz}{2}) = 0

t, 2 cos (t) = x

cos^{4} (x) = 1 - sin^{4} (x)

2 sinh (x) - 2 cosh (x) - 2 = 0

What is the general solution for sin(X)=(sqrt(2))/2 ?
The general solution for sin(X)=(sqrt(2))/2 is X= pi/4+2pin,X=(3pi)/4+2pin