What is the general solution for solvefor t,2cos(t)=x ?

The general solution for solvefor t,2cos(t)=x is t=arccos(x/2)+2pin,t=-arccos(x/2)+2pin

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solvefor t,2cos(t)=x

solve for

t, 2 cos (t) = x

t = arccos (\frac{x}{2}) + 2 πn, t = - arccos (\frac{x}{2}) + 2 πn

Solution steps

2 cos (t) = x

Divide both sides by

2

2 cos (t) = x

Divide both sides by

2

\frac{2 cos ( t )}{2} = \frac{x}{2}

Simplify

cos (t) = \frac{x}{2}

cos (t) = \frac{x}{2}

Apply trig inverse properties

cos (t) = \frac{x}{2}

General solutions for

cos (t) = \frac{x}{2}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

t = arccos (\frac{x}{2}) + 2 πn, t = - arccos (\frac{x}{2}) + 2 πn

t = arccos (\frac{x}{2}) + 2 πn, t = - arccos (\frac{x}{2}) + 2 πn

cos^{4} (x) = 1 - sin^{4} (x)

2 sinh (x) - 2 cosh (x) - 2 = 0

sec^{2} (x) + cot^{2} (x) = csc^{2} (x)

\frac{sin ( 7 9 ^{\circ} )}{12} = \frac{sin ( B )}{7}

\frac{( sin ^{2} ( x ) )}{( 1 - cos ( x ) )} = 1.23

What is the general solution for solvefor t,2cos(t)=x ?
The general solution for solvefor t,2cos(t)=x is t=arccos(x/2)+2pin,t=-arccos(x/2)+2pin