What is the general solution for 2tan(x)-2=0,0<= x<= 2pi ?

The general solution for 2tan(x)-2=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4

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2tan(x)-2=0,0<= x<= 2pi

2 tan (x) - 2 = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Degrees

x = 4 5^{\circ}, x = 22 5^{\circ}

Solution steps

2 tan (x) - 2 = 0, 0 \leq x \leq 2 π

Move

2

to the right side

2 tan (x) - 2 = 0

Add

2

to both sides

2 tan (x) - 2 + 2 = 0 + 2

Simplify

2 tan (x) = 2

2 tan (x) = 2

Divide both sides by

2

2 tan (x) = 2

Divide both sides by

2

\frac{2 tan ( x )}{2} = \frac{2}{2}

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

tan (3 5^{\circ}) tan (5 6^{\circ} - x) = 1

42.25 = 0.1681 cos (b)

\frac{tan ( 3 x )}{tan ( 2 x )} = 1

6 cot (x) = 5 - tan (x)

3 cos (θ) - 3 = 0

What is the general solution for 2tan(x)-2=0,0<= x<= 2pi ?
The general solution for 2tan(x)-2=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4