solvefor θ,cos(θ)=-cos(40)

Lösung

löse nach

θ, cos (θ) = - cos (4 0^{\circ})

θ = 2.44346 \dots + 36 0^{\circ} n, θ = - 2.44346 \dots + 36 0^{\circ} n

Radianten

θ = 2.44346 \dots + 2 πn, θ = - 2.44346 \dots + 2 πn

Schritte zur Lösung

cos (θ) = - cos (4 0^{\circ})

Wende die Eigenschaften der Trigonometrie an

cos (θ) = - cos (4 0^{\circ})

Allgemeine Lösung für

cos (θ) = - cos (4 0^{\circ})

cos (x) = - a \Rightarrow x = arccos (- a) + 36 0^{\circ} n, x = - arccos (- a) + 36 0^{\circ} n

θ = arccos (- cos (4 0^{\circ})) + 36 0^{\circ} n, θ = - arccos (- cos (4 0^{\circ})) + 36 0^{\circ} n

θ = arccos (- cos (4 0^{\circ})) + 36 0^{\circ} n, θ = - arccos (- cos (4 0^{\circ})) + 36 0^{\circ} n

Zeige Lösungen in Dezimalform

θ = 2.44346 \dots + 36 0^{\circ} n, θ = - 2.44346 \dots + 36 0^{\circ} n

7 sin (B) + 3 = sin (B) + 2

4 cos (x) = 3

cos (x + \frac{1}{6} π) cos (x - \frac{1}{6} π) = cos (2 x)

sin (x) = 0.731

sin (x) = 0.766