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受欢迎的三角函数 >

cos(2x+30)= 1/2 ,0<= x<= 360

解答

cos (2 x + 30) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

解答

x = \frac{- 90 + 522 0 ^{\circ}}{6}

+1

弧度

x = \frac{- 90 + 29 π}{6}

求解步骤

cos (2 x + 30) = \frac{1}{2}, 0^{\circ} \leq x \leq 36 0^{\circ}

cos (2 x + 30) = \frac{1}{2}

的通解

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n, 2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n, 2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n

解

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n : x = - 15 + 18 0^{\circ} n + 3 0^{\circ}

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n

将

30

到右边

2 x + 30 = 6 0^{\circ} + 36 0^{\circ} n

两边减去

30

2 x + 30 - 30 = 6 0^{\circ} + 36 0^{\circ} n - 30

化简

2 x = 6 0^{\circ} + 36 0^{\circ} n - 30

2 x = 6 0^{\circ} + 36 0^{\circ} n - 30

两边除以

2

2 x = 6 0^{\circ} + 36 0^{\circ} n - 30

两边除以

2

\frac{2 x}{2} = \frac{6 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2}

化简

\frac{2 x}{2} = \frac{6 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{6 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2} : - 15 + 18 0^{\circ} n + 3 0^{\circ}

\frac{6 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2}

对同类项分组

= - \frac{30}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{6 0 ^{\circ}}{2}

\frac{30}{2} = 15

\frac{30}{2}

数字相除:

\frac{30}{2} = 15

= 15

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{6 0 ^{\circ}}{2} = 3 0^{\circ}

\frac{6 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{18 0 ^{\circ}}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= 3 0^{\circ}

= - 15 + 18 0^{\circ} n + 3 0^{\circ}

x = - 15 + 18 0^{\circ} n + 3 0^{\circ}

x = - 15 + 18 0^{\circ} n + 3 0^{\circ}

x = - 15 + 18 0^{\circ} n + 3 0^{\circ}

解

2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n : x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n

将

30

到右边

2 x + 30 = 30 0^{\circ} + 36 0^{\circ} n

两边减去

30

2 x + 30 - 30 = 30 0^{\circ} + 36 0^{\circ} n - 30

化简

2 x = 30 0^{\circ} + 36 0^{\circ} n - 30

2 x = 30 0^{\circ} + 36 0^{\circ} n - 30

两边除以

2

2 x = 30 0^{\circ} + 36 0^{\circ} n - 30

两边除以

2

\frac{2 x}{2} = \frac{30 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2}

化简

\frac{2 x}{2} = \frac{30 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{30 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2} : - 15 + 18 0^{\circ} n + 15 0^{\circ}

\frac{30 0 ^{\circ}}{2} + \frac{36 0 ^{\circ} n}{2} - \frac{30}{2}

对同类项分组

= - \frac{30}{2} + \frac{36 0 ^{\circ} n}{2} + \frac{30 0 ^{\circ}}{2}

\frac{30}{2} = 15

\frac{30}{2}

数字相除:

\frac{30}{2} = 15

= 15

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

\frac{30 0 ^{\circ}}{2} = 15 0^{\circ}

\frac{30 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{90 0 ^{\circ}}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= 15 0^{\circ}

= - 15 + 18 0^{\circ} n + 15 0^{\circ}

x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

x = - 15 + 18 0^{\circ} n + 3 0^{\circ}, x = - 15 + 18 0^{\circ} n + 15 0^{\circ}

在

0 \leq x \leq 36 0^{\circ}

范围内的解

x = \frac{- 90 + 522 0 ^{\circ}}{6}

作图

流行的例子

tan (θ) = \frac{43}{90}

2sin(2x+pi/3)=1

2 sin (2 x + \frac{π}{3}) = 1

tan(x)=(5+cos(x))/(6sin(x)cos(x))

tan (x) = \frac{5 + cos ( x )}{6 sin ( x ) cos ( x )}

cos (t) = \frac{21}{29}

cos(x)=sin(x-pi/3)

cos (x) = sin (x - \frac{π}{3})