What is the general solution for cos(t)= 21/29 ?

The general solution for cos(t)= 21/29 is t=0.76101…+2pin,t=2pi-0.76101…+2pin

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cos(t)= 21/29

cos (t) = \frac{21}{29}

t = 0.76101 \dots + 2 πn, t = 2 π - 0.76101 \dots + 2 πn

Degrees

t = 43.60281 \dots^{\circ} + 36 0^{\circ} n, t = 316.39718 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (t) = \frac{21}{29}

Apply trig inverse properties

cos (t) = \frac{21}{29}

General solutions for

cos (t) = \frac{21}{29}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

t = arccos (\frac{21}{29}) + 2 πn, t = 2 π - arccos (\frac{21}{29}) + 2 πn

t = arccos (\frac{21}{29}) + 2 πn, t = 2 π - arccos (\frac{21}{29}) + 2 πn

Show solutions in decimal form

t = 0.76101 \dots + 2 πn, t = 2 π - 0.76101 \dots + 2 πn

cos (x) = sin (x - \frac{π}{3})

sin (x + \frac{π}{4}) + sin (x + \frac{π}{4}) = - 1

cos (x) - sin^{2} (x) = 0

4 sin^{2} (x) + 9 = 12

tan (- 60 s) = - tan (6 0^{\circ})

What is the general solution for cos(t)= 21/29 ?
The general solution for cos(t)= 21/29 is t=0.76101…+2pin,t=2pi-0.76101…+2pin