What is the general solution for tan(2θ)=0.6583 ?

The general solution for tan(2θ)=0.6583 is θ=(0.58218…)/2+(pin)/2

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tan(2θ)=0.6583

tan (2 θ) = 0.6583

θ = \frac{0.58218 \dots}{2} + \frac{πn}{2}

Degrees

θ = 16.67845 \dots^{\circ} + 9 0^{\circ} n

Solution steps

tan (2 θ) = 0.6583

Apply trig inverse properties

tan (2 θ) = 0.6583

General solutions for

tan (2 θ) = 0.6583

tan (x) = a \Rightarrow x = arctan (a) + πn

2 θ = arctan (0.6583) + πn

2 θ = arctan (0.6583) + πn

Solve

2 θ = arctan (0.6583) + πn : θ = \frac{arctan ( 0.6583 )}{2} + \frac{πn}{2}

2 θ = arctan (0.6583) + πn

Divide both sides by

2

2 θ = arctan (0.6583) + πn

Divide both sides by

2

\frac{2 θ}{2} = \frac{arctan ( 0.6583 )}{2} + \frac{πn}{2}

Simplify

θ = \frac{arctan ( 0.6583 )}{2} + \frac{πn}{2}

θ = \frac{arctan ( 0.6583 )}{2} + \frac{πn}{2}

θ = \frac{arctan ( 0.6583 )}{2} + \frac{πn}{2}

Show solutions in decimal form

θ = \frac{0.58218 \dots}{2} + \frac{πn}{2}

sin (x) = \frac{8}{12.8}

3 tan^{2} (x) - 2 = 5 sec^{2} (x) - 9

x, z = arcsin^{3} (3 x + 2 y)

(3 sec (θ) - 23) (2 sin (θ) - 1) = 0, 2 π

7 cos (θ) - 3 = 3 sin^{2} (θ)

What is the general solution for tan(2θ)=0.6583 ?
The general solution for tan(2θ)=0.6583 is θ=(0.58218…)/2+(pin)/2