What is the general solution for 3-cos(6x)*6=0 ?

The general solution for 3-cos(6x)*6=0 is x= pi/(18)+(pin)/3 ,x=(5pi}{18}+\frac{pin)/3

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3-cos(6x)*6=0

Solution

3 - cos (6 x) \cdot 6 = 0

Solution

x = \frac{π}{18} + \frac{πn}{3}, x = \frac{5 π}{18} + \frac{πn}{3}

Degrees

x = 1 0^{\circ} + 6 0^{\circ} n, x = 5 0^{\circ} + 6 0^{\circ} n

Solution steps

3 - cos (6 x) \cdot 6 = 0

Move

3

to the right side

3 - cos (6 x) \cdot 6 = 0

Subtract

3

from both sides

3 - cos (6 x) \cdot 6 - 3 = 0 - 3

Simplify

- cos (6 x) \cdot 6 = - 3

- cos (6 x) \cdot 6 = - 3

Divide both sides by

- 6

- cos (6 x) \cdot 6 = - 3

Divide both sides by

- 6

\frac{- cos ( 6 x ) \cdot 6}{- 6} = \frac{- 3}{- 6}

Simplify

\frac{- cos ( 6 x ) \cdot 6}{- 6} = \frac{- 3}{- 6}

Simplify

\frac{- cos ( 6 x ) \cdot 6}{- 6} : cos (6 x)

\frac{- cos ( 6 x ) \cdot 6}{- 6}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{cos ( 6 x ) \cdot 6}{6}

Divide the numbers:

\frac{6}{6} = 1

= cos (6 x)

Simplify

\frac{- 3}{- 6} : \frac{1}{2}

\frac{- 3}{- 6}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3}{6}

Cancel the common factor:

3

= \frac{1}{2}

cos (6 x) = \frac{1}{2}

cos (6 x) = \frac{1}{2}

cos (6 x) = \frac{1}{2}

General solutions for

cos (6 x) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

6 x = \frac{π}{3} + 2 πn, 6 x = \frac{5 π}{3} + 2 πn

6 x = \frac{π}{3} + 2 πn, 6 x = \frac{5 π}{3} + 2 πn

Solve

6 x = \frac{π}{3} + 2 πn : x = \frac{π}{18} + \frac{πn}{3}

6 x = \frac{π}{3} + 2 πn

Divide both sides by

6

6 x = \frac{π}{3} + 2 πn

Divide both sides by

6

\frac{6 x}{6} = \frac{\frac{π}{3}}{6} + \frac{2 πn}{6}

Simplify

\frac{6 x}{6} = \frac{\frac{π}{3}}{6} + \frac{2 πn}{6}

Simplify

\frac{6 x}{6} : x

\frac{6 x}{6}

Divide the numbers:

\frac{6}{6} = 1

= x

Simplify

\frac{\frac{π}{3}}{6} + \frac{2 πn}{6} : \frac{π}{18} + \frac{πn}{3}

\frac{\frac{π}{3}}{6} + \frac{2 πn}{6}

\frac{\frac{π}{3}}{6} = \frac{π}{18}

\frac{\frac{π}{3}}{6}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 6}

Multiply the numbers:

3 \cdot 6 = 18

= \frac{π}{18}

\frac{2 πn}{6} = \frac{πn}{3}

\frac{2 πn}{6}

Cancel the common factor:

2

= \frac{πn}{3}

= \frac{π}{18} + \frac{πn}{3}

x = \frac{π}{18} + \frac{πn}{3}

x = \frac{π}{18} + \frac{πn}{3}

x = \frac{π}{18} + \frac{πn}{3}

Solve

6 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{18} + \frac{πn}{3}

6 x = \frac{5 π}{3} + 2 πn

Divide both sides by

6

6 x = \frac{5 π}{3} + 2 πn

Divide both sides by

6

\frac{6 x}{6} = \frac{\frac{5 π}{3}}{6} + \frac{2 πn}{6}

Simplify

\frac{6 x}{6} = \frac{\frac{5 π}{3}}{6} + \frac{2 πn}{6}

Simplify

\frac{6 x}{6} : x

\frac{6 x}{6}

Divide the numbers:

\frac{6}{6} = 1

= x

Simplify

\frac{\frac{5 π}{3}}{6} + \frac{2 πn}{6} : \frac{5 π}{18} + \frac{πn}{3}

\frac{\frac{5 π}{3}}{6} + \frac{2 πn}{6}

\frac{\frac{5 π}{3}}{6} = \frac{5 π}{18}

\frac{\frac{5 π}{3}}{6}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 6}

Multiply the numbers:

3 \cdot 6 = 18

= \frac{5 π}{18}

\frac{2 πn}{6} = \frac{πn}{3}

\frac{2 πn}{6}

Cancel the common factor:

2

= \frac{πn}{3}

= \frac{5 π}{18} + \frac{πn}{3}

x = \frac{5 π}{18} + \frac{πn}{3}

x = \frac{5 π}{18} + \frac{πn}{3}

x = \frac{5 π}{18} + \frac{πn}{3}

x = \frac{π}{18} + \frac{πn}{3}, x = \frac{5 π}{18} + \frac{πn}{3}

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Frequently Asked Questions (FAQ)

What is the general solution for 3-cos(6x)*6=0 ?
The general solution for 3-cos(6x)*6=0 is x= pi/(18)+(pin)/3 ,x=(5pi}{18}+\frac{pin)/3