What is the general solution for cos(x)= 2/(sqrt(29)) ?

The general solution for cos(x)= 2/(sqrt(29)) is x=1.19028…+2pin,x=2pi-1.19028…+2pin

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cos(x)= 2/(sqrt(29))

cos (x) = \frac{2}{29}

x = 1.19028 \dots + 2 πn, x = 2 π - 1.19028 \dots + 2 πn

Radians

x = 1.19028 \dots + 6.28318 \dots n, x = 5.09289 \dots + 6.28318 \dots n

Solution steps

cos (x) = \frac{2}{29}

Simplify

\frac{2}{29} : \frac{2 29}{29}

\frac{2}{29}

Multiply by the conjugate

\frac{29}{29}

= \frac{2 29}{29 29}

2929 = 29

2929

Apply radical rule:

a a = a

2929 = 29

= 29

= \frac{2 29}{29}

cos (x) = \frac{2 29}{29}

Apply trig inverse properties

cos (x) = \frac{2 29}{29}

General solutions for

cos (x) = \frac{2 29}{29}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{2 29}{29}) + 2 πn, x = 2 π - arccos (\frac{2 29}{29}) + 2 πn

x = arccos (\frac{2 29}{29}) + 2 πn, x = 2 π - arccos (\frac{2 29}{29}) + 2 πn

Show solutions in decimal form

x = 1.19028 \dots + 2 πn, x = 2 π - 1.19028 \dots + 2 πn

2 cos (\frac{x}{2}) = cos (x) + 1

cos (x) = 100

1.58 \cdot sin (3 4^{\circ}) = 1 (sin (θ))

10 sin (x) + 4 = 10

4. 3^{2} = 3. 8^{2} + 6. 3^{2} + 2 (3.8) (6.3) cos (b)

What is the general solution for cos(x)= 2/(sqrt(29)) ?
The general solution for cos(x)= 2/(sqrt(29)) is x=1.19028…+2pin,x=2pi-1.19028…+2pin