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Beliebt Trigonometrie >

1.58*sin(34)=1(sin(θ))

Lösung

1.58 \cdot sin (3 4^{\circ}) = 1 (sin (θ))

Lösung

θ = 1.08333 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 1.08333 \dots + 36 0^{\circ} n

+1

Radianten

θ = 1.08333 \dots + 2 πn, θ = π - 1.08333 \dots + 2 πn

Schritte zur Lösung

1.58 sin (3 4^{\circ}) = 1 \cdot (sin (θ))

Tausche die Seiten

1 \cdot sin (θ) = 1.58 sin (3 4^{\circ})

Multipliziere:

1 \cdot sin (θ) = sin (θ)

sin (θ) = 1.58 sin (3 4^{\circ})

Wende die Eigenschaften der Trigonometrie an

sin (θ) = 1.58 sin (3 4^{\circ})

Allgemeine Lösung für

sin (θ) = 1.58 sin (3 4^{\circ})

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (1.58 sin (3 4^{\circ})) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (1.58 sin (3 4^{\circ})) + 36 0^{\circ} n

θ = arcsin (1.58 sin (3 4^{\circ})) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (1.58 sin (3 4^{\circ})) + 36 0^{\circ} n

Zeige Lösungen in Dezimalform

θ = 1.08333 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 1.08333 \dots + 36 0^{\circ} n

Graph

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