What is the general solution for sin(θ)=-3/5 ,cos(θ)= 4/5 ,tan(θ),cot(θ) ?

The general solution for sin(θ)=-3/5 ,cos(θ)= 4/5 ,tan(θ),cot(θ) is No Solution for θ\in\mathbb{R}

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sin(θ)=-3/5 ,cos(θ)= 4/5 ,tan(θ),cot(θ)

sin (θ) = - \frac{3}{5}, cos (θ) = \frac{4}{5}, tan (θ), cot (θ)

No Solution for θ \in R

Solution steps

sin (θ) = - \frac{3}{5}, cos (θ) = \frac{4}{5}, tan (θ), cot (θ)

Apply trig inverse properties

sin (θ) = - \frac{3}{5}

General solutions for

sin (θ) = - \frac{3}{5}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

θ = arcsin (- \frac{3}{5}) + 2 πn, θ = π + arcsin (\frac{3}{5}) + 2 πn

θ = arcsin (- \frac{3}{5}) + 2 πn, θ = π + arcsin (\frac{3}{5}) + 2 πn

Solutions for the range

cos (θ) = \frac{4}{5}

No Solution for θ \in R

cos (6 0^{\circ} - x) = 1

sec^{2} (θ) + csc^{2} (θ) = 1

cos (t) - sin (t) = 0

sin (x) - cos (x) = \frac{1}{3}

tan^{2} (x) = sec (x) - 1, 0 \leq x \leq 2 π

What is the general solution for sin(θ)=-3/5 ,cos(θ)= 4/5 ,tan(θ),cot(θ) ?
The general solution for sin(θ)=-3/5 ,cos(θ)= 4/5 ,tan(θ),cot(θ) is No Solution for θ\in\mathbb{R}