What is the general solution for cos(θ)=0.3,cos(2θ) ?

The general solution for cos(θ)=0.3,cos(2θ) is No Solution for θ\in\mathbb{R}

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cos(θ)=0.3,cos(2θ)

cos (θ) = 0.3, cos (2 θ)

No Solution for θ \in R

Solution steps

cos (θ) = 0.3, cos (2 θ)

Apply trig inverse properties

cos (θ) = 0.3

General solutions for

cos (θ) = 0.3

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (0.3) + 2 πn, θ = 2 π - arccos (0.3) + 2 πn

θ = arccos (0.3) + 2 πn, θ = 2 π - arccos (0.3) + 2 πn

Solutions for the range

cos (2 θ)

No Solution for θ \in R

(- \frac{2}{3})^{2} + 1 = sec (θ)

1 = sech^{2} (x)

tan (θ) = 0.86667

sin (x) \cdot cos^{2} (x) = 1

t, f w = 2 + cos (10 π t)

What is the general solution for cos(θ)=0.3,cos(2θ) ?
The general solution for cos(θ)=0.3,cos(2θ) is No Solution for θ\in\mathbb{R}