What is the general solution for tan(2x)=-(-270-120)/(130) ?

The general solution for tan(2x)=-(-270-120)/(130) is x=(1.24904…)/2+(pin)/2

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tan(2x)=-(-270-120)/(130)

tan (2 x) = - \frac{- 270 - 120}{130}

x = \frac{1.24904 \dots}{2} + \frac{πn}{2}

Radians

x = \frac{1.24904 \dots}{2} + \frac{π}{2} n

Solution steps

tan (2 x) = - \frac{- 270 - 120}{130}

Simplify

- \frac{- 270 - 120}{130} : 3

- \frac{- 270 - 120}{130}

Subtract the numbers:

- 270 - 120 = - 390

= - \frac{- 390}{130}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - (- \frac{390}{130})

Divide the numbers:

\frac{390}{130} = 3

= - (- 3)

Apply rule

- (- a) = a

= 3

Apply trig inverse properties

tan (2 x) = 3

General solutions for

tan (2 x) = 3

tan (x) = a \Rightarrow x = arctan (a) + πn

2 x = arctan (3) + πn

2 x = arctan (3) + πn

Solve

2 x = arctan (3) + πn : x = \frac{arctan ( 3 )}{2} + \frac{πn}{2}

2 x = arctan (3) + πn

Divide both sides by

2

2 x = arctan (3) + πn

Divide both sides by

2

\frac{2 x}{2} = \frac{arctan ( 3 )}{2} + \frac{πn}{2}

Simplify

x = \frac{arctan ( 3 )}{2} + \frac{πn}{2}

x = \frac{arctan ( 3 )}{2} + \frac{πn}{2}

x = \frac{arctan ( 3 )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{1.24904 \dots}{2} + \frac{πn}{2}

3 tan (x + 4 3^{\circ}) = 2 cos (x + 4 3^{\circ})

\frac{sec ^{2} ( - 1 )}{tan ( x )} = tan (x)

4 sin (x) = 3 sec (x)

\frac{sin ( 55.01 - x )}{sin ( x )} = \frac{1200}{500}

csc (θ) = 0.77

What is the general solution for tan(2x)=-(-270-120)/(130) ?
The general solution for tan(2x)=-(-270-120)/(130) is x=(1.24904…)/2+(pin)/2