What is the general solution for (sin(x)+cos(x))/(sin(x))=1 1/(tan(x)) ?

The general solution for (sin(x)+cos(x))/(sin(x))=1 1/(tan(x)) is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sin(x)+cos(x))/(sin(x))=1 1/(tan(x))

Solution

\frac{sin ( x ) + cos ( x )}{sin ( x )} = 1 \frac{1}{tan ( x )}

Solution

No Solution for x \in R

Solution steps

\frac{sin ( x ) + cos ( x )}{sin ( x )} = 1 \cdot \frac{1}{tan ( x )}

Subtract

1 \frac{1}{tan ( x )}

from both sides

\frac{sin ( x ) + cos ( x )}{sin ( x )} - \frac{1}{tan ( x )} = 0

Simplify

\frac{sin ( x ) + cos ( x )}{sin ( x )} - \frac{1}{tan ( x )} : \frac{tan ( x ) ( sin ( x ) + cos ( x ) ) - sin ( x )}{sin ( x ) tan ( x )}

\frac{sin ( x ) + cos ( x )}{sin ( x )} - \frac{1}{tan ( x )}

Least Common Multiplier of

sin (x), tan (x) : sin (x) tan (x)

sin (x), tan (x)

Lowest Common Multiplier (LCM)

Compute an expression comprised of factors that appear either in

sin (x)

tan (x)

= sin (x) tan (x)

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

sin (x) tan (x)

For

\frac{sin ( x ) + cos ( x )}{sin ( x )} :

multiply the denominator and numerator by

tan (x)

\frac{sin ( x ) + cos ( x )}{sin ( x )} = \frac{( sin ( x ) + cos ( x ) ) tan ( x )}{sin ( x ) tan ( x )}

For

\frac{1}{tan ( x )} :

multiply the denominator and numerator by

sin (x)

\frac{1}{tan ( x )} = \frac{1 \cdot sin ( x )}{tan ( x ) sin ( x )} = \frac{sin ( x )}{sin ( x ) tan ( x )}

= \frac{( sin ( x ) + cos ( x ) ) tan ( x )}{sin ( x ) tan ( x )} - \frac{sin ( x )}{sin ( x ) tan ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( sin ( x ) + cos ( x ) ) tan ( x ) - sin ( x )}{sin ( x ) tan ( x )}

\frac{tan ( x ) ( sin ( x ) + cos ( x ) ) - sin ( x )}{sin ( x ) tan ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

tan (x) (sin (x) + cos (x)) - sin (x) = 0

Rewrite using trig identities

- sin (x) + (cos (x) + sin (x)) tan (x)

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - sin (x) + (cos (x) + sin (x)) \frac{sin ( x )}{cos ( x )}

Simplify

- sin (x) + (cos (x) + sin (x)) \frac{sin ( x )}{cos ( x )} : \frac{sin ^{2} ( x )}{cos ( x )}

- sin (x) + (cos (x) + sin (x)) \frac{sin ( x )}{cos ( x )}

Multiply

(cos (x) + sin (x)) \frac{sin ( x )}{cos ( x )} : \frac{sin ( x ) ( cos ( x ) + sin ( x ) )}{cos ( x )}

(cos (x) + sin (x)) \frac{sin ( x )}{cos ( x )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) ( cos ( x ) + sin ( x ) )}{cos ( x )}

= - sin (x) + \frac{sin ( x ) ( cos ( x ) + sin ( x ) )}{cos ( x )}

Convert element to fraction:

sin (x) = \frac{sin ( x ) cos ( x )}{cos ( x )}

= \frac{sin ( x ) ( cos ( x ) + sin ( x ) )}{cos ( x )} - \frac{sin ( x ) cos ( x )}{cos ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ( x ) ( cos ( x ) + sin ( x ) ) - sin ( x ) cos ( x )}{cos ( x )}

Expand

sin (x) (cos (x) + sin (x)) - sin (x) cos (x) : sin^{2} (x)

sin (x) (cos (x) + sin (x)) - sin (x) cos (x)

Expand

sin (x) (cos (x) + sin (x)) : sin (x) cos (x) + sin^{2} (x)

sin (x) (cos (x) + sin (x))

Apply the distributive law:

a (b + c) = ab + a c

a = sin (x), b = cos (x), c = sin (x)

= sin (x) cos (x) + sin (x) sin (x)

sin (x) sin (x) = sin^{2} (x)

sin (x) sin (x)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= sin^{1 + 1} (x)

Add the numbers:

1 + 1 = 2

= sin^{2} (x)

= sin (x) cos (x) + sin^{2} (x)

= sin (x) cos (x) + sin^{2} (x) - sin (x) cos (x)

Add similar elements:

sin (x) cos (x) - sin (x) cos (x) = 0

= sin^{2} (x)

= \frac{sin ^{2} ( x )}{cos ( x )}

= \frac{sin ^{2} ( x )}{cos ( x )}

\frac{sin ^{2} ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

Since the equation is undefined for:

2 πn, π + 2 πn

No Solution for x \in R

Popular Examples

arctan(x)=(-pi)/2

arctan (x) = \frac{- π}{2}

cot(θ)=-sqrt(3),sin(2θ)

cot (θ) = - 3, sin (2 θ)

3sin(2x)-1cos(x)=0

3 sin (2 x) - 1 cos (x) = 0

sin(4x-3)=cos(5x-6)

sin (4 x - 3) = cos (5 x - 6)

6sin(2x-30)+2=0

6 sin (2 x - 3 0^{\circ}) + 2 = 0

Frequently Asked Questions (FAQ)

What is the general solution for (sin(x)+cos(x))/(sin(x))=1 1/(tan(x)) ?
The general solution for (sin(x)+cos(x))/(sin(x))=1 1/(tan(x)) is No Solution for x\in\mathbb{R}