What is the general solution for cos(B)= 2/3 ?

The general solution for cos(B)= 2/3 is B=0.84106…+2pin,B=2pi-0.84106…+2pin

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cos(B)= 2/3

cos (B) = \frac{2}{3}

B = 0.84106 \dots + 2 πn, B = 2 π - 0.84106 \dots + 2 πn

Degrees

B = 48.18968 \dots^{\circ} + 36 0^{\circ} n, B = 311.81031 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (B) = \frac{2}{3}

Apply trig inverse properties

cos (B) = \frac{2}{3}

General solutions for

cos (B) = \frac{2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

B = arccos (\frac{2}{3}) + 2 πn, B = 2 π - arccos (\frac{2}{3}) + 2 πn

B = arccos (\frac{2}{3}) + 2 πn, B = 2 π - arccos (\frac{2}{3}) + 2 πn

Show solutions in decimal form

B = 0.84106 \dots + 2 πn, B = 2 π - 0.84106 \dots + 2 πn

tan (θ) sin (θ) = 3 sin (θ)

sin (2 x) = 1 - sin (2 x)

3 tan (c) + 8 = 0

cos^{2} (x) - 2 cos (x) - 2 = 0

tan (x) = \frac{14.9}{13.3}

What is the general solution for cos(B)= 2/3 ?
The general solution for cos(B)= 2/3 is B=0.84106…+2pin,B=2pi-0.84106…+2pin