What is the general solution for tan(θ)=0.02 ?

The general solution for tan(θ)=0.02 is θ=0.01999…+pin

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tan(θ)=0.02

tan (θ) = 0.02

θ = 0.01999 \dots + πn

Degrees

θ = 1.14576 \dots^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = 0.02

Apply trig inverse properties

tan (θ) = 0.02

General solutions for

tan (θ) = 0.02

tan (x) = a \Rightarrow x = arctan (a) + πn

θ = arctan (0.02) + πn

θ = arctan (0.02) + πn

Show solutions in decimal form

θ = 0.01999 \dots + πn

cos (x) = 0.123

- 2 cos (2 θ) - 4 sin (θ) + 2 = - 5 sin (θ)

5 cos^{2} (x) - 4 = 0

cos (x) = \frac{1.2}{1.4}

θ, cos (θ) + cos (9 0^{\circ} - θ) = 0

What is the general solution for tan(θ)=0.02 ?
The general solution for tan(θ)=0.02 is θ=0.01999…+pin