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Popular Trigonometry >

sin(A)-0.6*cos(A)=(2.77)/(9.8)

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Solution

sin(A)−0.6⋅cos(A)=9.82.77​

Solution

A=−2.84598…+2πn,A=0.78523…+2πn
+1
Degrees
A=−163.06288…∘+360∘n,A=44.99039…∘+360∘n
Solution steps
sin(A)−0.6cos(A)=9.82.77​
Add 0.6cos(A) to both sidessin(A)=0.28265…+0.6cos(A)
Square both sidessin2(A)=(0.28265…+0.6cos(A))2
Subtract (0.28265…+0.6cos(A))2 from both sidessin2(A)−0.07989…−0.33918…cos(A)−0.36cos2(A)=0
Rewrite using trig identities
−0.07989…+sin2(A)−0.33918…cos(A)−0.36cos2(A)
Use the Pythagorean identity: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−0.07989…+1−cos2(A)−0.33918…cos(A)−0.36cos2(A)
Simplify −0.07989…+1−cos2(A)−0.33918…cos(A)−0.36cos2(A):−1.36cos2(A)−0.33918…cos(A)+0.92010…
−0.07989…+1−cos2(A)−0.33918…cos(A)−0.36cos2(A)
Group like terms=−cos2(A)−0.33918…cos(A)−0.36cos2(A)−0.07989…+1
Add similar elements: −cos2(A)−0.36cos2(A)=−1.36cos2(A)=−1.36cos2(A)−0.33918…cos(A)−0.07989…+1
Add/Subtract the numbers: −0.07989…+1=0.92010…=−1.36cos2(A)−0.33918…cos(A)+0.92010…
=−1.36cos2(A)−0.33918…cos(A)+0.92010…
0.92010…−0.33918…cos(A)−1.36cos2(A)=0
Solve by substitution
0.92010…−0.33918…cos(A)−1.36cos2(A)=0
Let: cos(A)=u0.92010…−0.33918…u−1.36u2=0
0.92010…−0.33918…u−1.36u2=0:u=−2.720.33918…+5.12042…​​,u=2.725.12042…​−0.33918…​
0.92010…−0.33918…u−1.36u2=0
Write in the standard form ax2+bx+c=0−1.36u2−0.33918…u+0.92010…=0
Solve with the quadratic formula
−1.36u2−0.33918…u+0.92010…=0
Quadratic Equation Formula:
For a=−1.36,b=−0.33918…,c=0.92010…u1,2​=2(−1.36)−(−0.33918…)±(−0.33918…)2−4(−1.36)⋅0.92010…​​
u1,2​=2(−1.36)−(−0.33918…)±(−0.33918…)2−4(−1.36)⋅0.92010…​​
(−0.33918…)2−4(−1.36)⋅0.92010…​=5.12042…​
(−0.33918…)2−4(−1.36)⋅0.92010…​
Apply rule −(−a)=a=(−0.33918…)2+4⋅1.36⋅0.92010…​
Apply exponent rule: (−a)n=an,if n is even(−0.33918…)2=0.33918…2=0.33918…2+4⋅0.92010…⋅1.36​
Multiply the numbers: 4⋅1.36⋅0.92010…=5.00538…=0.33918…2+5.00538…​
0.33918…2=0.11504…=0.11504…+5.00538…​
Add the numbers: 0.11504…+5.00538…=5.12042…=5.12042…​
u1,2​=2(−1.36)−(−0.33918…)±5.12042…​​
Separate the solutionsu1​=2(−1.36)−(−0.33918…)+5.12042…​​,u2​=2(−1.36)−(−0.33918…)−5.12042…​​
u=2(−1.36)−(−0.33918…)+5.12042…​​:−2.720.33918…+5.12042…​​
2(−1.36)−(−0.33918…)+5.12042…​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅1.360.33918…+5.12042…​​
Multiply the numbers: 2⋅1.36=2.72=−2.720.33918…+5.12042…​​
Apply the fraction rule: −ba​=−ba​=−2.720.33918…+5.12042…​​
u=2(−1.36)−(−0.33918…)−5.12042…​​:2.725.12042…​−0.33918…​
2(−1.36)−(−0.33918…)−5.12042…​​
Remove parentheses: (−a)=−a,−(−a)=a=−2⋅1.360.33918…−5.12042…​​
Multiply the numbers: 2⋅1.36=2.72=−2.720.33918…−5.12042…​​
Apply the fraction rule: −b−a​=ba​0.33918…−5.12042…​=−(5.12042…​−0.33918…)=2.725.12042…​−0.33918…​
The solutions to the quadratic equation are:u=−2.720.33918…+5.12042…​​,u=2.725.12042…​−0.33918…​
Substitute back u=cos(A)cos(A)=−2.720.33918…+5.12042…​​,cos(A)=2.725.12042…​−0.33918…​
cos(A)=−2.720.33918…+5.12042…​​,cos(A)=2.725.12042…​−0.33918…​
cos(A)=−2.720.33918…+5.12042…​​:A=arccos(−2.720.33918…+5.12042…​​)+2πn,A=−arccos(−2.720.33918…+5.12042…​​)+2πn
cos(A)=−2.720.33918…+5.12042…​​
Apply trig inverse properties
cos(A)=−2.720.33918…+5.12042…​​
General solutions for cos(A)=−2.720.33918…+5.12042…​​cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnA=arccos(−2.720.33918…+5.12042…​​)+2πn,A=−arccos(−2.720.33918…+5.12042…​​)+2πn
A=arccos(−2.720.33918…+5.12042…​​)+2πn,A=−arccos(−2.720.33918…+5.12042…​​)+2πn
cos(A)=2.725.12042…​−0.33918…​:A=arccos(2.725.12042…​−0.33918…​)+2πn,A=2π−arccos(2.725.12042…​−0.33918…​)+2πn
cos(A)=2.725.12042…​−0.33918…​
Apply trig inverse properties
cos(A)=2.725.12042…​−0.33918…​
General solutions for cos(A)=2.725.12042…​−0.33918…​cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnA=arccos(2.725.12042…​−0.33918…​)+2πn,A=2π−arccos(2.725.12042…​−0.33918…​)+2πn
A=arccos(2.725.12042…​−0.33918…​)+2πn,A=2π−arccos(2.725.12042…​−0.33918…​)+2πn
Combine all the solutionsA=arccos(−2.720.33918…+5.12042…​​)+2πn,A=−arccos(−2.720.33918…+5.12042…​​)+2πn,A=arccos(2.725.12042…​−0.33918…​)+2πn,A=2π−arccos(2.725.12042…​−0.33918…​)+2πn
Verify solutions by plugging them into the original equation
Check the solutions by plugging them into sin(A)−0.6cos(A)=9.82.77​
Remove the ones that don't agree with the equation.
Check the solution arccos(−2.720.33918…+5.12042…​​)+2πn:False
arccos(−2.720.33918…+5.12042…​​)+2πn
Plug in n=1arccos(−2.720.33918…+5.12042…​​)+2π1
For sin(A)−0.6cos(A)=9.82.77​plug inA=arccos(−2.720.33918…+5.12042…​​)+2π1sin(arccos(−2.720.33918…+5.12042…​​)+2π1)−0.6cos(arccos(−2.720.33918…+5.12042…​​)+2π1)=9.82.77​
Refine0.86529…=0.28265…
⇒False
Check the solution −arccos(−2.720.33918…+5.12042…​​)+2πn:True
−arccos(−2.720.33918…+5.12042…​​)+2πn
Plug in n=1−arccos(−2.720.33918…+5.12042…​​)+2π1
For sin(A)−0.6cos(A)=9.82.77​plug inA=−arccos(−2.720.33918…+5.12042…​​)+2π1sin(−arccos(−2.720.33918…+5.12042…​​)+2π1)−0.6cos(−arccos(−2.720.33918…+5.12042…​​)+2π1)=9.82.77​
Refine0.28265…=0.28265…
⇒True
Check the solution arccos(2.725.12042…​−0.33918…​)+2πn:True
arccos(2.725.12042…​−0.33918…​)+2πn
Plug in n=1arccos(2.725.12042…​−0.33918…​)+2π1
For sin(A)−0.6cos(A)=9.82.77​plug inA=arccos(2.725.12042…​−0.33918…​)+2π1sin(arccos(2.725.12042…​−0.33918…​)+2π1)−0.6cos(arccos(2.725.12042…​−0.33918…​)+2π1)=9.82.77​
Refine0.28265…=0.28265…
⇒True
Check the solution 2π−arccos(2.725.12042…​−0.33918…​)+2πn:False
2π−arccos(2.725.12042…​−0.33918…​)+2πn
Plug in n=12π−arccos(2.725.12042…​−0.33918…​)+2π1
For sin(A)−0.6cos(A)=9.82.77​plug inA=2π−arccos(2.725.12042…​−0.33918…​)+2π1sin(2π−arccos(2.725.12042…​−0.33918…​)+2π1)−0.6cos(2π−arccos(2.725.12042…​−0.33918…​)+2π1)=9.82.77​
Refine−1.13132…=0.28265…
⇒False
A=−arccos(−2.720.33918…+5.12042…​​)+2πn,A=arccos(2.725.12042…​−0.33918…​)+2πn
Show solutions in decimal formA=−2.84598…+2πn,A=0.78523…+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for sin(A)-0.6*cos(A)=(2.77)/(9.8) ?

    The general solution for sin(A)-0.6*cos(A)=(2.77)/(9.8) is A=-2.84598…+2pin,A=0.78523…+2pin
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