What is the general solution for arccos(x)= pi/3 ?

The general solution for arccos(x)= pi/3 is x= 1/2

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arccos(x)= pi/3

arccos (x) = \frac{π}{3}

x = \frac{1}{2}

Solution steps

arccos (x) = \frac{π}{3}

Apply trig inverse properties

arccos (x) = \frac{π}{3}

arccos (x) = a \Rightarrow x = cos (a)

x = cos (\frac{π}{3})

cos (\frac{π}{3}) = \frac{1}{2}

cos (\frac{π}{3})

Use the following trivial identity:

cos (\frac{π}{3}) = \frac{1}{2}

cos (\frac{π}{3})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= \frac{1}{2}

x = \frac{1}{2}

x = \frac{1}{2}

arccos (x) = \frac{π}{2}

2 cos (2 θ) = 1

a^{2} cos (θ) sin (θ) = 0

6 sec^{2} (9 x) - 5 = 7

2 sin^{2} (\frac{x}{2}) - 3 cos (\frac{x}{2}) = 0

What is the general solution for arccos(x)= pi/3 ?
The general solution for arccos(x)= pi/3 is x= 1/2