What is the general solution for sin(x)= 5/10 ?

The general solution for sin(x)= 5/10 is x= pi/6+2pin,x=(5pi)/6+2pin

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sin(x)= 5/10

sin (x) = \frac{5}{10}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Degrees

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) = \frac{5}{10}

Cancel the common factor:

5

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

(cos (x) - 1) (cos (x) - 2) = 0

tan (θ) = \frac{4}{- 3}

tan (3 x + 2 6^{\circ}) = cot (5 x)

sin (x) = \frac{3}{5}, \frac{π}{2} \leq x \leq π

2 sin^{2} (θ) + cos (θ) = 2

What is the general solution for sin(x)= 5/10 ?
The general solution for sin(x)= 5/10 is x= pi/6+2pin,x=(5pi)/6+2pin