What is the general solution for 0=sin(c) ?

The general solution for 0=sin(c) is c=2pin,c=pi+2pin

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0=sin(c)

0 = sin (c)

c = 2 πn, c = π + 2 πn

Degrees

c = 0^{\circ} + 36 0^{\circ} n, c = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

0 = sin (c)

Switch sides

sin (c) = 0

General solutions for

sin (c) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

c = 0 + 2 πn, c = π + 2 πn

c = 0 + 2 πn, c = π + 2 πn

Solve

c = 0 + 2 πn : c = 2 πn

c = 0 + 2 πn

0 + 2 πn = 2 πn

c = 2 πn

c = 2 πn, c = π + 2 πn

sin (θ) = - \frac{5}{13}, sec (θ)

3 cosh (x) + 5 sinh (x) = - 3

sin (a) = 2 (1 - cos (a))

4 + 4 tan (θ) = 0

tan (2 x + 3) = 1

What is the general solution for 0=sin(c) ?
The general solution for 0=sin(c) is c=2pin,c=pi+2pin