What is the general solution for cos(a)= 1/(sqrt(3)) ?

The general solution for cos(a)= 1/(sqrt(3)) is a=0.95531…+2pin,a=2pi-0.95531…+2pin

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cos(a)= 1/(sqrt(3))

cos (a) = \frac{1}{3}

a = 0.95531 \dots + 2 πn, a = 2 π - 0.95531 \dots + 2 πn

Radians

a = 0.95531 \dots + 6.28318 \dots n, a = 5.32786 \dots + 6.28318 \dots n

Solution steps

cos (a) = \frac{1}{3}

Simplify

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

cos (a) = \frac{3}{3}

Apply trig inverse properties

cos (a) = \frac{3}{3}

General solutions for

cos (a) = \frac{3}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

a = arccos (\frac{3}{3}) + 2 πn, a = 2 π - arccos (\frac{3}{3}) + 2 πn

a = arccos (\frac{3}{3}) + 2 πn, a = 2 π - arccos (\frac{3}{3}) + 2 πn

Show solutions in decimal form

a = 0.95531 \dots + 2 πn, a = 2 π - 0.95531 \dots + 2 πn

tan (θ) = - \frac{7}{4}

2 sin (x) tan (x) + 1 = tan (x) + 2 sin (x)

sec (y) = (\frac{5}{4})

\frac{sin ( 6 5 ^{\circ} )}{5} = \frac{sin ( x )}{4}

2 - 6.5 sin (x) = 0

What is the general solution for cos(a)= 1/(sqrt(3)) ?
The general solution for cos(a)= 1/(sqrt(3)) is a=0.95531…+2pin,a=2pi-0.95531…+2pin