zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

sin(x/2)+sin(x/2)=sin(x)

解答

sin (\frac{x}{2}) + sin (\frac{x}{2}) = sin (x)

解答

x = 4 πn, x = 2 π + 4 πn

+1

度数

x = 0^{\circ} + 72 0^{\circ} n, x = 36 0^{\circ} + 72 0^{\circ} n

求解步骤

sin (\frac{x}{2}) + sin (\frac{x}{2}) = sin (x)

两边减去

sin (x)

2 sin (\frac{x}{2}) - sin (x) = 0

令

: u = \frac{x}{2}

2 sin (u) - sin (2 u) = 0

使用三角恒等式改写

- sin (2 u) + 2 sin (u)

使用倍角公式:

sin (2 x) = 2 sin (x) cos (x)

= - 2 sin (u) cos (u) + 2 sin (u)

2 sin (u) - 2 cos (u) sin (u) = 0

分解

2 sin (u) - 2 cos (u) sin (u) : - 2 sin (u) (cos (u) - 1)

2 sin (u) - 2 cos (u) sin (u)

因式分解出通项

- 2 sin (u)

= - 2 sin (u) (- 1 + cos (u))

- 2 sin (u) (cos (u) - 1) = 0

分别求解每个部分

sin (u) = 0 or cos (u) - 1 = 0

sin (u) = 0 : u = 2 πn, u = π + 2 πn

sin (u) = 0

sin (u) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

u = 0 + 2 πn, u = π + 2 πn

u = 0 + 2 πn, u = π + 2 πn

解

u = 0 + 2 πn : u = 2 πn

u = 0 + 2 πn

0 + 2 πn = 2 πn

u = 2 πn

u = 2 πn, u = π + 2 πn

cos (u) - 1 = 0 : u = 2 πn

cos (u) - 1 = 0

将

1

到右边

cos (u) - 1 = 0

两边加上

1

cos (u) - 1 + 1 = 0 + 1

化简

cos (u) = 1

cos (u) = 1

cos (u) = 1

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

u = 0 + 2 πn

u = 0 + 2 πn

解

u = 0 + 2 πn : u = 2 πn

u = 0 + 2 πn

0 + 2 πn = 2 πn

u = 2 πn

u = 2 πn

合并所有解

u = 2 πn, u = π + 2 πn

u = \frac{x}{2}

代回

\frac{x}{2} = 2 πn : x = 4 πn

\frac{x}{2} = 2 πn

在两边乘以

2

\frac{x}{2} = 2 πn

在两边乘以

2

\frac{2 x}{2} = 2 \cdot 2 πn

化简

x = 4 πn

x = 4 πn

\frac{x}{2} = π + 2 πn : x = 2 π + 4 πn

\frac{x}{2} = π + 2 πn

在两边乘以

2

\frac{x}{2} = π + 2 πn

在两边乘以

2

\frac{2 x}{2} = 2 π + 2 \cdot 2 πn

化简

x = 2 π + 4 πn

x = 2 π + 4 πn

x = 4 πn, x = 2 π + 4 πn

作图

流行的例子

15cos(x)-5=4cos(x)

15 cos (x) - 5 = 4 cos (x)

cos(x)-cos(2x)=0,0<= x<= 2pi

cos (x) - cos (2 x) = 0, 0 \leq x \leq 2 π

2+cos(2x)=-5sin(x)

2 + cos (2 x) = - 5 sin (x)

cos^2(θ)-1/4 =0

cos^{2} (θ) - \frac{1}{4} = 0

2cot(x)+sec^2(x)=0

2 cot (x) + sec^{2} (x) = 0