What is the derivative of f(x)=x^2+1 ?

The derivative of f(x)=x^2+1 is 2x

What is the first derivative of f(x)=x^2+1 ?

The first derivative of f(x)=x^2+1 is 2x

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derivative of

f (x) = x^{2} + 1

2 x

Solution steps

\frac{d}{d x} (x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

(2.3) (4.9)

(15, - 3), (5, 12)

y = \frac{2}{3} x - 3, (0, - 3)

(22, 22)

f (x) = ln (x), at x = 1

What is the derivative of f(x)=x^2+1 ?
The derivative of f(x)=x^2+1 is 2x
What is the first derivative of f(x)=x^2+1 ?
The first derivative of f(x)=x^2+1 is 2x