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Popular >

midpoint (15,-3),(5,12)

Solution

midpoint

(15, - 3), (5, 12)

Solution

(10, \frac{9}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (15, - 3), (x_{2}, y_{2}) = (5, 12)

= (\frac{5 + 15}{2}, \frac{12 - 3}{2})

Refine

= (10, \frac{9}{2})

Popular Examples

perpendicular y= 2/3 x-3,(0,-3)perpendicular

y = \frac{2}{3} x - 3, (0, - 3)

polar (2sqrt(2),2sqrt(2))cartesian to polar

(22, 22)

tangent of f(x)=ln(x),\at x=1 tangent of

f (x) = ln (x), at x = 1

polar (4sqrt(3),4)cartesian to polar

(43, 4)

integral of x integral

x

Frequently Asked Questions (FAQ)

What is the midpoint (15,-3),(5,12) ?
The midpoint (15,-3),(5,12) is (10, 9/2)