What is the perpendicular y= 2/3 x-3,(0,-3) ?

The perpendicular y= 2/3 x-3,(0,-3) is y=-3/2 x-3

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perpendicular y= 2/3 x-3,(0,-3)

perpendicular

y = \frac{2}{3} x - 3, (0, - 3)

y = - \frac{3}{2} x - 3

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{2}{3} x - 3

that passes through

(0, - 3)

Find the slope of

y = \frac{2}{3} x - 3 : m = \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(0, - 3) : y = - \frac{3}{2} x - 3

y = - \frac{3}{2} x - 3

(22, 22)

f (x) = ln (x), at x = 1

(43, 4)

x

y = \frac{2}{3} x

What is the perpendicular y= 2/3 x-3,(0,-3) ?
The perpendicular y= 2/3 x-3,(0,-3) is y=-3/2 x-3