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受欢迎的初等代数 >

19+14\div 10× 4-24

解答

19 + 14 \div 10 \times 4 - 24

解答

\frac{3}{5}

+1

十进制

0.6

求解步骤

19 + 14 \div 10 \times 4 - 24

遵循 PEMDAS 运算顺序

乘除（左右）

14 \div 10 \times 4 : \frac{28}{5}

14 \div 10 \times 4

14 \div 10 = \frac{14}{10}

= \frac{14}{10} \times 4

\frac{14}{10} \times 4 = \frac{28}{5}

\frac{14}{10} \cdot 4

消掉

\frac{14}{10} : \frac{7}{5}

\frac{14}{10}

因式分解数字:

14 = 2 \cdot 7

= \frac{2 \cdot 7}{10}

因式分解数字:

10 = 2 \cdot 5

= \frac{2 \cdot 7}{2 \cdot 5}

约分:

2

= \frac{7}{5}

= \frac{7}{5} \cdot 4

\frac{7}{5} \cdot 4 = \frac{28}{5}

\frac{7}{5} \cdot 4

将项转换为分式:

4 = \frac{4}{1}

= \frac{7}{5} \cdot \frac{4}{1}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{7 \cdot 4}{5 \cdot 1}

数字相乘:

7 \cdot 4 = 28

= \frac{28}{5 \cdot 1}

数字相乘:

5 \cdot 1 = 5

= \frac{28}{5}

= \frac{28}{5}

= \frac{28}{5}

= 19 + \frac{28}{5} - 24

加减（左右）

19 + \frac{28}{5} - 24 : \frac{3}{5}

19 + \frac{28}{5} - 24

19 + \frac{28}{5} = \frac{123}{5}

19 + \frac{28}{5}

将项转换为分式:

19 = \frac{19 \cdot 5}{5}

= \frac{19 \cdot 5}{5} + \frac{28}{5}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{19 \cdot 5 + 28}{5}

19 \cdot 5 + 28 = 123

19 \cdot 5 + 28

数字相乘:

19 \cdot 5 = 95

= 95 + 28

数字相加:

95 + 28 = 123

= 123

= \frac{123}{5}

= \frac{123}{5} - 24

\frac{123}{5} - 24 = \frac{3}{5}

\frac{123}{5} - 24

将项转换为分式:

24 = \frac{24 \cdot 5}{5}

= - \frac{24 \cdot 5}{5} + \frac{123}{5}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 24 \cdot 5 + 123}{5}

- 24 \cdot 5 + 123 = 3

- 24 \cdot 5 + 123

数字相乘:

24 \cdot 5 = 120

= - 120 + 123

数字相加/相减:

- 120 + 123 = 3

= 3

= \frac{3}{5}

= \frac{3}{5}

= \frac{3}{5}

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4^{2} + 4^{3}

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4^{2} + [3^{5} \times (2^{3} - 5^{2})]

\frac{7}{3} \cdot 7 \div 2

6^{3} + 5 (8 + \frac{1}{5})

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