What is the axis 3x^2=-12y ?

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axis 3x^2=-12y

axis

3 x^{2} = - 12 y

x = 0

Solution steps

3 x^{2} = - 12 y

Rewrite

3 x^{2} = - 12 y

in the standard form:

4 (- 1) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 1

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x 4 x - y = 7

y = x^{2} - 2 x - 24

y = 18 x^{2} + 14 x

x = (y)^{4} + 6 (y)^{2} - 1

x^{2} - 24 y + 48 = 0