What is the axis x^2-24y+48=0 ?

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axis x^2-24y+48=0

axis

x^{2} - 24 y + 48 = 0

x = 0

Solution steps

x^{2} - 24 y + 48 = 0

Rewrite

x^{2} - 24 y + 48 = 0

in the standard form:

4 \cdot 6 (y - 2) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = 6

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2 x^{2} + 8 x + 4

y = 48 x - 6 x^{2}

y = 3 x^{2} + 6 x - 45

x = 14 (y - 4) (y + 10)

y = x^{2} - 2 x - 18