What is the axis y=3x^2+6x-45 ?

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axis y=3x^2+6x-45

axis

y = 3 x^{2} + 6 x - 45

x = - 1

Solution steps

y = 3 x^{2} + 6 x - 45

Rewrite

y = 3 x^{2} + 6 x - 45

in the standard form

4 \cdot \frac{1}{12} (y - (- 48)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 48), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

x = 14 (y - 4) (y + 10)

y = x^{2} - 2 x - 18

y = \frac{( 4 x + 5 ) ( 2 x + 3 )}{2}

y = x \cdot (x + 1)

y = - 4 x^{2}