What is the axis x=(sqrt(y))^4+6(sqrt(y))^2-1 ?

The axis x=(sqrt(y))^4+6(sqrt(y))^2-1 is y=-3

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axis x=(sqrt(y))^4+6(sqrt(y))^2-1

axis

x = (y)^{4} + 6 (y)^{2} - 1

y = - 3

Solution steps

x = (y)^{4} + 6 (y)^{2} - 1

Rewrite

x = (y)^{4} + 6 (y)^{2} - 1

in the standard form

4 \cdot \frac{1}{4} (x - (- 10)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 10, - 3), p = \frac{1}{4}

EN : P a r ab o l e S y mm e t ry A x i s T i tl e 2 Eq

y = - 3

What is the axis x=(sqrt(y))^4+6(sqrt(y))^2-1 ?
The axis x=(sqrt(y))^4+6(sqrt(y))^2-1 is y=-3