What is the axis y=-4x^2+48x ?

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axis y=-4x^2+48x

axis

y = - 4 x^{2} + 48 x

x = 6

Solution steps

y = - 4 x^{2} + 48 x

Rewrite

y = - 4 x^{2} + 48 x

in the standard form

4 (- \frac{1}{16}) (y - 144) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, 144), p = - \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 6

3 x^{2} = - 12 y

x 4 x - y = 7

y = x^{2} - 2 x - 24

y = 18 x^{2} + 14 x

x = (y)^{4} + 6 (y)^{2} - 1