What is the axis y=-x^2-2x ?

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axis y=-x^2-2x

axis

y = - x^{2} - 2 x

x = - 1

Solution steps

y = - x^{2} - 2 x

Rewrite

y = - x^{2} - 2 x

in the standard form

4 (- \frac{1}{4}) (y - 1) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 1), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y + 5 x^{2} = 4

y = 2 x^{2} + 3

y^{2} - 8 x - 6 y - 23 = 0

y = (x - 5) (x - 1)

y = 2 x^{2} - 8 x + 3