What is the axis y=2x^2-8x+3 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=2x^2-8x+3

axis

y = 2 x^{2} - 8 x + 3

x = 2

Solution steps

y = 2 x^{2} - 8 x + 3

Rewrite

y = 2 x^{2} - 8 x + 3

in the standard form

4 \cdot \frac{1}{8} (y - (- 5)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 5), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = - 16 x^{2} + 48 x + 100

y^{2} - 10 x + 4 y - 16 = 0

y = - 12 x^{2} + 156 x

y^{2} + 2 x - 2 y - 3 = 0

y = 2 x^{2} - x