What is the axis y=(x-5)(x-1) ?

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axis y=(x-5)(x-1)

axis

y = (x - 5) (x - 1)

x = 3

Solution steps

y = (x - 5) (x - 1)

Rewrite

y = (x - 5) (x - 1)

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = 2 x^{2} - 8 x + 3

y = - 16 x^{2} + 48 x + 100

y^{2} - 10 x + 4 y - 16 = 0

y = - 12 x^{2} + 156 x

y^{2} + 2 x - 2 y - 3 = 0