What is the axis y=(x-(24)/(x+2))(x-(12)/(x-4)) ?

The axis y=(x-(24)/(x+2))(x-(12)/(x-4)) is x=0

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axis y=(x-(24)/(x+2))(x-(12)/(x-4))

axis

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

x = 0

Solution steps

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

Rewrite

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

in the standard form

4 \cdot \frac{1}{4} (y - (- 36)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 36), p = \frac{1}{4}

EN : P a r ab o l e S y mm e t ry A x i s T i tl e 2 Eq

x = 0

What is the axis y=(x-(24)/(x+2))(x-(12)/(x-4)) ?
The axis y=(x-(24)/(x+2))(x-(12)/(x-4)) is x=0