What is the axis y^2+4x+1=0 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y^2+4x+1=0

axis

y^{2} + 4 x + 1 = 0

y = 0

Solution steps

y^{2} + 4 x + 1 = 0

Rewrite

y^{2} + 4 x + 1 = 0

in the standard form:

4 (- 1) (x - (- \frac{1}{4})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, 0), p = - 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = - \frac{1}{6} x^{2} + 4 x + 10

f (x) = - (x - 9)^{2} - 30

x^{2} - 4 x - 5

y = 5 \cdot (x + 7 + 149) (x + 7 - 149)

30 x^{2} + 90 x + y + 64 = 0