What is the axis y=4+2x-x^2 ?

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axis y=4+2x-x^2

axis

y = 4 + 2 x - x^{2}

x = 1

Solution steps

y = 4 + 2 x - x^{2}

Rewrite

y = 4 + 2 x - x^{2}

in the standard form

4 (- \frac{1}{4}) (y - 5) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 5), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = - \frac{2}{5} x^{2} + 4 x

y = - x^{2} - 6 \cdot x + 7

y = x^{2} - 3 x + 5

y = \frac{3}{8} x^{2}

y = - (0.009 (x - 220)^{2} - 220)