What is the axis y=x^2-3x+5 ?

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axis y=x^2-3x+5

axis

y = x^{2} - 3 x + 5

x = \frac{3}{2}

Solution steps

y = x^{2} - 3 x + 5

Rewrite

y = x^{2} - 3 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - \frac{11}{4}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{11}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

y = \frac{3}{8} x^{2}

y = - (0.009 (x - 220)^{2} - 220)

(x - 4)^{2} = 8 (y - 3)

y = - 2 x^{2} + 6 x + 10

y = - 3 (x + 6)^{2} + 4