What is the axis y=x^2-3x+5 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

axis y=x^2-3x+5

axis

x = \frac{3}{2}

Solution steps

y = x^{2} - 3 x + 5

Rewrite

y = x^{2} - 3 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - \frac{11}{4}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{11}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}